x^2-3=(x-3)/2

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Solution for x^2-3=(x-3)/2 equation: 


x in (-oo:+oo)

x^2-3 = (x-3)/2 // - (x-3)/2

x^2-((x-3)/2)-3 = 0

(-1*(x-3))/2+x^2-3 = 0

(-1*(x-3))/2+(2*x^2)/2+(-3*2)/2 = 0

2*x^2-1*(x-3)-3*2 = 0

2*x^2-x-6+3 = 0

2*x^2-x-3 = 0

2*x^2-x-3 = 0

2*x^2-x-3 = 0

DELTA = (-1)^2-(-3*2*4)

DELTA = 25

DELTA > 0

x = (25^(1/2)+1)/(2*2) or x = (1-25^(1/2))/(2*2)

x = 3/2 or x = -1

(x+1)*(x-3/2) = 0

((x+1)*(x-3/2))/2 = 0

((x+1)*(x-3/2))/2 = 0 // * 2

(x+1)*(x-3/2) = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x-3/2 )

x-3/2 = 0 // + 3/2

x = 3/2

x in { -1, 3/2 }

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